b^2+10b+28=0

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Solution for b^2+10b+28=0 equation:


Simplifying
b2 + 10b + 28 = 0

Reorder the terms:
28 + 10b + b2 = 0

Solving
28 + 10b + b2 = 0

Solving for variable 'b'.

Begin completing the square.

Move the constant term to the right:

Add '-28' to each side of the equation.
28 + 10b + -28 + b2 = 0 + -28

Reorder the terms:
28 + -28 + 10b + b2 = 0 + -28

Combine like terms: 28 + -28 = 0
0 + 10b + b2 = 0 + -28
10b + b2 = 0 + -28

Combine like terms: 0 + -28 = -28
10b + b2 = -28

The b term is 10b.  Take half its coefficient (5).
Square it (25) and add it to both sides.

Add '25' to each side of the equation.
10b + 25 + b2 = -28 + 25

Reorder the terms:
25 + 10b + b2 = -28 + 25

Combine like terms: -28 + 25 = -3
25 + 10b + b2 = -3

Factor a perfect square on the left side:
(b + 5)(b + 5) = -3

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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